Solutions-Class-8-Mathematics-Chapter-9-Discount and Commission-MSBSHSE

Discount and Commission

Class-8-Mathematics-Chapter-9-Maharashtra Board

Solutions

Practice Set 9.1

Question 1.1. If marked price = 1700, selling price = 1540 then find the discount.

Solution :

M.P. = ₹ 1700, S.P. = ₹ 1540; Discount =?

Discount = M.P. - S.P. = ₹ (1700 - 1540) = ₹ 160

Answer is : The discount is ₹ 160.

Question 1.2. If marked price = 990 and percentage of discount is 10, then find the selling price.

Solution :

M.P. =₹ 990; Discount = 10%; S.P. =?

Let the discount given be ₹ x

\(\frac{Discount}{Marked\,Price}\) = \(\frac{Discount%}{100}\)

\(\frac{x}{990}\) = \(\frac{10}{100}\)

x = \(\frac{10×990}{100}\)  = ₹ 99

S.P. = M.P. - Discount

= ₹ (990 - 99) = ₹ 891

Answer is : The selling price is ₹ 891.

Question 1.3. If selling price = 900. Discount is 20 %, then find the marked price.

Solution :

Let the M.P. (marked price) be ₹ 100.

Discount = 20%. discount = ₹ 20.

∴ S.P. = M.P. – discount = ₹ (100 - 20) = ₹ 80.

If the selling price is ₹ 80, the marked price is ₹ 100. Let us assume that the M.P. is ₹ x,

Question 1.4. The marked price of the fan is 3000 rupees. Shopkeeper gave 12% discount on it. Find the total discount and selling price of the fan.

Solution :

 (i) Given Information:

  • Marked Price (M.P.) = Rs. 3000
  • Percentage of Discount = 12%

(ii) Calculate the Total Discount:

Total Discount = M.P. × \(\frac{Discount%}{100}\) = 3000 × \(\frac{12}{100}\) = Rs. 360

 (iii) Calculate the Selling Price:

The selling price is found by subtracting the discount from the marked price: Selling Price = Marked Price – Discount = 3000 – 360 = 2640

Final Answer:

  • The total discount is Rs. 360.
  • The selling price of the fan is Rs. 2640.

Question 1.5. The marked price of a mixer is 2300 rupees. A customer purchased it for Rs.1955. Find percentage of discount offered to the customer.

Solution :

(i) Given Information:

  • Marked Price = Rs. 2300
  • Selling Price = Rs. 1955

(ii) Calculate the Discount Amount:

Discount = Marked Price - Selling Price = 2300 – 1955 = Rs. 345

(iii) Calculate the Percentage of Discount:

Let the percentage of discount be x

\(\frac{Discount}{Marked\,Price}\) = \(\frac{Discount%}{100}\)

\(\frac{345}{2300}\) = \(\frac{x}{100}\)

∴ x = \(\frac{345×100}{2300}\) = 15

Final Answer: The percentage of discount offered to the customer is 15%.

Question 1.6. A shopkeeper gives 11% discount on a television set, hence the cost price of it is Rs. 22,250. Then find the marked price of the television set.

Solution :

(i) Given Information:

  • Percentage of Discount = 11%
  • Selling Price (amount paid by the customer) = Rs. 22,250

(ii) Assume a base price:

 Suppose the marked price of the television set was Rs. 100.

Since the discount is 11%, the customer would get it for 100 - 11 = 89 rupees. This means if the selling price is Rs. 89, the marked price is Rs. 100.

Let x be the actual marked price of the television set.

(iii) Solve for x:

\(\frac{Selling\,Price}{Marked\,Price}\) = \(\frac{89}{100}\)

 \(\frac{22250}{x}\) = \(\frac{89}{100}\)

∴ x =  \(\frac{22250×100}{89}\) = 250 × 100 = 25000

Final Answer: The marked price of the television set is Rs. 25,000.

Question 1.7. After offering discount of 10% on marked price, a customer gets total discount of 17 rupees. To find the cost price for the customer, fill in the following boxes with appropriate numbers and complete the activity.

Suppose, marked price of the item = 100 rupees

Therefore, for customer that item costs [?] – [?] = 90 rupees

Hence, when the discount is [?] then the selling price is [?] rupees.

Suppose when the discount is [?] rupees, the selling price is x rupees.

\(\frac{x}{[?]}\) = \(\frac{[?]}{[?]}\) x = \(\frac{[?]×[?]}{[?]}\) = [?]

∴ the customer will get the item for 153 rupees.

Solution :

Suppose, marked price of the item = 100 rupees

Therefore, for customer that item costs [100] – [10] = 90 rupees

Hence, when the discount is [₹ 10] then the selling price is [₹ 90] rupees.

Suppose when the discount is [₹ 17] rupees, the selling price is x rupees.

∴ \(\frac{x}{[90]}\) = \(\frac{[17]}{[10]}\) ∴ x = \(\frac{[17]×[90]}{[10]}\) = [153]

∴ the customer will get the item for 153 rupees.

Question 1.8. A shopkeeper decides to sell a certain item at a certain price. He tags the price on the item by increasing the decided price by 25%. While selling the item, he offers 20% discount. Find how many more or less percent he gets on the decided price.

Solution :

 Let the decided price be Rs. 100.

The shopkeeper increases the decided price by 25% to set the marked price.

  • Increase = 25% of 100 = Rs. 25
  • Marked Price = 100 + 25 = Rs. 125

 The shopkeeper offers a 20% discount on the marked price.

  • Discount = 20% of 125
  • Discount = \(\frac{20}{100}\) × 125
  • Discount = \(\frac{1}{5}\) × 125 = Rs. 25

The selling price = M.P. - Discount.

  • Selling Price = 125 – 25 = Rs. 100

Determine the percentage difference:

  • Decided Price = Rs. 100
  • Selling Price = Rs. 100

Since the selling price is exactly equal to the decided price, the shopkeeper gets 0% more or less on the decided price.

Practice Set 9.2

Question 2.1. John sold books worth rupees 4500 for a publisher. For this he received 15 % commission. Complete the following activity to find the total commission John obtained.

Selling price of books = [?], Rate of commission = [?]

Commission obtained = \(\frac{[?]}{[?]}\) × [?] Commission = [?] rupees

Solution :

Selling price of books = [4500], Rate of commission = [15]

Commission obtained = \(\frac{[15]}{[100]}\) × [4500] ∴ Commission = [675] rupees

Question 2.2. Rafique sold flowers worth 15,000 by giving 4% commission to the agent. Find the commission he paid. Find the amount received by Rafique.

Solution :

(i) Given Information:

  • Total value of flowers sold (Selling Price): Rs. 15,000
  • Rate of commission: 4%

(ii) Calculate the Commission Paid:

Commission = Selling Price × Percentage commission

= 15,000 × \(\frac{4}{100}\)  = 150 × 4 = 600

Commission = Rs. 600

(iii) Calculate the Amount Received by Rafique:

Amount Received = Selling Price – Commission = 15,000 – 600 = 14400

Amount Received = Rs. 14,400

Final Answer:

  • The commission Rafique paid is Rs. 600.
  • The total amount received by Rafique is Rs. 14,400.

Question 2.3. A farmer sold foodgrains for 9200 rupees through an agent. The rate of commission was 2%. How much amount did the agent get?

Solution :

(i) Given Information:

  • Selling Price of foodgrains: Rs. 9200
  • Rate of commission: 2%

(ii) Calculate the Commission:

Commission = Selling Price × Percentage commission

= 9200 × \(\frac{2}{100}\)  = 92 × 2 = 184

Commission = Rs. 184

Final Answer: The agent received Rs. 184 for the transaction.

Question 2.4. Umatai purchased following items from a Khadi - Bhandar.

(i) 3 sarees for 560 rupees each.

(ii) 6 bottles of honey for 90 rupees each.

On the purchase, she received a rebate of 12%. How much total amount did Umatai pay ?

Solution :

(i) Calculate the total cost of items purchased:

  • Cost of 3 sarees = 3 × 560 = Rs. 1680
  • Cost of 6 bottles of honey = 6 × 90 = \ Rs. 540
  • Total Cost Price = 1680 + 540 = Rs. 2220

(ii) Calculate the total rebate:

A rebate is a type of discount often given by organizations like Khadi-Gramodyog on special occasions.

  • Rebate Percentage = 12%
  • Rebate Amount = \(\frac{12}{100}\)  × 2220 = 12 × 22.2 = Rs. 266.40

(iii) Calculate the total amount paid: The amount to be paid is the total cost minus the rebate amount:

  • Total Amount Paid = 2220 - 266.40 = Rs. 1953.60

Final Answer: Umatai paid a total of Rs. 1953.60.

Question 2.5. Use the given information and fill in the boxes with suitable numbers.

Smt. Deepanjali purchased a house for 7,50,000 from Smt. Leelaben through an agent. Agent has charged 2 % brokerage from both of them.

(1) Smt. Deepanjali paid [?] × \(\frac{[?]}{[?]}\) = [?]  brokerage for purchasing the house.

(2) Smt. Leelaben paid brokerage of [?].

(3) Total brokerage received by the agent is [?].

(4) The cost of house Smt. Deepanjali paid is [?].

(5) The selling price of house for Smt. Leelaben is [?].

Solution :

(1) Smt. Deepanjali paid [750000] × \(\frac{[2]}{[100]}\)  = ₹ [15000]  brokerage for purchasing the house.

(2) Smt. Leelaben paid brokerage of ₹ [15,000].

(3) Total brokerage received by the agent is ₹ [30,000].

(4) The cost of house Smt. Deepanjali paid is ₹ [7,65,000].

(5) The selling price of house for Smt. Leelaben is ₹ [7,35,000].

Explanation :

(2) Brokerage is the same from both.

(4) The cost of house = purchase price + brokerage

(5) The selling price of house = price of house - brokerage

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