Solutions-Class-8-Mathematics-Chapter-11-Statistics-MSBSHSE

Statistics

Class-8-Mathematics-Chapter-11-Maharashtra Board

Solutions

Practice Set 11.1

Question 1.1. The following table shows the number of saplings planted by 30 students. Fill in the boxes and find the average number of saplings planted by each student.

No. of saplings (Scores) xi No. of students (frequency) fi fi × xi
1 4 4
2 6 [?]
3 12 [?]
4 8 [?]
N = [?] Σ fixi = [?]

Mean (\(\bar{x}\)) = \(\frac{[?]}{N}\) =\(\frac{[?]}{[?]}\)= [?]

The average number of trees planted [?]

Solution :

No. of saplings (Scores) xi No. of students (frequency) fi fi × xi
1 4 4
2 6 [12]
3 12 [36]
4 8 [32]
N = [30] Σ fixi = [84]

Mean (\(\bar{x}\)) = \(\frac{∑f_ix_i}{N}\) = \(\frac{84}{30}\) = [2.8]

The average number of trees planted [2.8]

Question 1.2. The following table shows the electricity (in units) used by 25 families of Eklara village in a month of May. Complete the table and answer the following questions.

Electricity used (Units) xi No. of families (frequency) fi fi × xi
30 7 ……
45 2 ……
60 8 ……
75 5 ……
90 3 ……
N = ….. Σ fix= …

(1) How many families use 45 units electricity ?

(2) State the score, the frequency of which is 5.

(3) Find N, and Σ fix

(4) Find the mean of electricity used by each family in the month of May.

Solution :

Electricity used (Units) xi No. of families (frequency) fi fi × xi
30 7 210
45 2 90
60 8 480
75 5 375
90 3 270
N = 25 Σ fix= 1425

(1) 2 families

(2) The score is 75

(3) N = 25; Σ fixi  = 1425

(4) Mean (\(\bar{x}\)) = \(\frac{∑f_ix_i}{N}\) = \(\frac{1425}{25}\) = 57

The mean of electricity used by each family is 57 units.

Question 1.3. The number of members in the 40 families in Bhilar are as follows: 1, 6, 5, 4, 3, 2, 7, 2, 3, 4, 5, 6, 4, 6, 2, 3, 2, 1, 4, 5, 6, 7, 3, 4, 5, 2, 4, 3, 2, 3, 5, 5, 4, 6, 2, 3, 5, 6, 4, 2. Prepare a frequency table and find the mean of members of 40 families.

Solution :

Number of members xi Tally marks Number of families fi fi × xi
1 || 2 2
2 |||| ||| 8 16
3 |||| || 7 21
4 |||| ||| 8 32
5 |||| || 7 35
6 |||| | 6 36
8 2 14
N = 40 Σ fix= 156

Mean (\(\bar{x}\)) = \(\frac{∑f_ix_i}{N}\) = \(\frac{156}{40}\) = 3.9

Answer is : The mean of members of families = 3.9

Question 1.4. The number of Science and Mathematics projects submitted by Model high school, Nandpur in last 20 years at the state level science exhibition is : 2, 3, 4, 1, 2, 3, 1, 5, 4, 2, 3, 1, 3, 5, 4, 3, 2, 2, 3, 2. Prepare a frequency table and find the mean of the data.

Solution :

Number of projects xi Tally Marks Number of years fi fi × xi
1 ||| 3 3
2 |||| | 6 12
3 |||| | 6 18
4 ||| 3 12
5 || 2 10
N = 20 Σ fix= 55

Mean (\(\bar{x}\)) = \(\frac{∑f_ix_i}{N}\) = \(\frac{55}{20}\) = 2.75

Answer is : Mean of the data = 2.75

Practice Set 11.2

Question 2.1. Observe the following graph and answer the questions.

(1) State the type of the graph.

(2) How much is the savings of Vaishali in the month of April?

(3) How much is the total of savings of Saroj in the months March and April?

(4) How much more is the total savings of Savita than the total savings of Megha?

(5) Whose savings in the month of April is the least?

Solution :

(1) The given graph is a subdivided bar graph.

(2) The savings of Vaishali in the month of April is ₹ 600.

(3) The total of savings of Saroj in the months of March and April is ₹ 800.

(4) The total savings by Savita is ₹ 1000 and that by Megha is ₹ 500. ₹ (1000-500) = ₹ 500.

The total savings by Savita is ₹ 500 more than that of Megha.

(5) The savings of Megha is the least in the month of April.

Question 2.2. The number of boys and girls, in std 5 to std 8 in a Z.P. school is given in the table. Draw a subdivided bar graph to show the data.

(Scale : On Y axis, 1cm= 10 students)

Standard 5th 6th 7th 8th
Boys 34 26 21 25
Girls 17 14 14 20
Solution :

Standard 5th 6th 7th 8th
Boys 34 26 21 25
Girls 17 14 14 20
Total 51 40 35 45

Question 2.3. In the following table number of trees planted in the year 2016 and 2017 in four towns is given. Show the data with the help of subdivided bar graph.

Town

year

Karjat Wadgoan Shivapur Khandala
2016 150 250 200 100
2017 200 300 250 150
Solution :

Town

year

Karjat Wadgoan Shivapur Khandala
2016 150 250 200 100
2017 200 300 250 150
Total 350 550 450 250

Question 2.4. In the following table, data of the transport means used by students in 8th standard for commutation between home and school is given. Draw a subdivided bar diagram to show the data. (Scale : On Y axis : 1 cm = 500 students)

Town

Mean of commutation

Paithan Yeola Shahapur
cycle 3250 1500 1250
Bus and Auto 750 500 500
On foot 1000 1000 500
Solution :

Town

Mean of commutation

Paithan Yeola Shahapur
cycle 3250 1500 1250
Bus and Auto 750 500 500
On foot 1000 1000 500
Total 5000 3000 2250

Practice Set 11.3

Question 3.1. Show the following information by a percentage bar graph.

Division of standard 8 A B C D
Number of students securing grade A 45 33 10 15
Total number of students 60 55 40 75
Solution :

Division of standard 8 A B C D
Number of students securing grade A 45 33 10 15
Total number of students 60 55 40 75
Percentage of students securing grade A \(\frac{45}{60}\) x 100 = 75 \(\frac{33}{55}\) x 100 = 60 \(\frac{10}{400}\) x 100 = 25 \(\frac{15}{75}\) x 100 = 20
Percentage of the remaining students 100 – 75 = 25 100 – 60 = 40 100 – 25 = 75 100 – 20 = 80

Question 3.2. Observe the following graph and answer the questions

(1) State the type of the bar graph.

(2) How much percent is the Tur production to total production in Ajita’s farm ?

(3) Compare the production of Gram in the farms of Yash and Ravi and state whose percentage of production is more and by how much ?

(4) Whose percentage production of Tur is the least?

(5) State production percentages of Tur and gram in Sudha’s farm.

Solution :

(1) It is a percentage bar graph.

(2) The Tur production is 60 %.

(3) Gram production : Yash's farm : 50%; Ravi's farm : 30%. Gram production in Yash's farm is more by 20% [50 - 20].

(4) The percentage production of Tur is least in Sudha's farm.

(5) The percentage production of Tur in Sudha's farm : 40% and the percentage production of gram : 60%.

Question 3.3. The following data is collected in a survey of some students of 10th standard from some schools. Draw the percentage bar graph of the data.

School 1st 2nd 3rd 4th
Inclination towards science stream 90 60 25 16
Inclination towards commerce stream 60 20 25 24
Solution :

School 1st 2nd 3rd 4th
Inclination towards science stream 90 60 25 16
Inclination towards commerce stream 60 20 25 24
Total 150 80 50 40
Percent inclination towards science stream \(\frac{90}{150}\) x 100 = 60 \(\frac{60}{80}\) x 100 = 75 \(\frac{25}{50}\) x 100 = 50 \(\frac{16}{40}\) x 100 = 40
Percent inclination towards commerce stream 100 – 60 = 40 100 – 75 = 25 100 – 50 = 50 100 – 40 = 60

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