Notes-Class-8-Mathematics-Chapter-15-Area-MSBSHSE

Area

Class-8-Mathematics-Chapter-15-Maharashtra Board

Notes

Topics to be learn :

  • Area of a parallelogram
  • Area of a rhombus
  • Area of a trapezium
  • Area of a Triangle
  • Area of figures having irregular shape
  • Area of a circle

Area :

Area is the measure of the region enclosed by a closed polygon. It is measured in square units because the calculation is fundamentally based on the number of squares that can fit within the boundary.

Basic Shape Formulas

  1. Square: Area = side2
  2. Rectangle: Area = length × breadth
  3. Right-angled Triangle: Area = \(\frac{1}{2}\) × product of sides making the right angle
  4. Standard Triangle: Area = \(\frac{1}{2}\) × base × height

Area of Quadrilaterals :

Area of a parallelogram :

A quadrilateral is a parallelogram if both the pairs of its opposite sides are parallel and equal.

The area of a parallelogram is equivalent to the area of a rectangle with the same base and height.

Formula: Area =  base × height

Key Insight:

If one parallel side is considered the base, the height is the perpendicular distance between the two parallel sides.

Multiple bases can be used; for instance, in parallelogram ABCD, the area can be expressed as l(BC) × h or l(AB) × k, where h and k are heights corresponding to those specific bases.

Area of a rhombus :

The area of a rhombus is derived from the properties of its diagonals, which are perpendicular bisectors of each other. This divides the rhombus into four congruent right-angled triangles.

  • Formula: Area = \(\frac{1}{2}\) × product of lengths of diagonals
  • Side Calculation: If the diagonals and area are known, the side of the rhombus can be found using the Pythagoras theorem within one of the internal right-angled triangles (where sides are half the lengths of the diagonals).

Example :

□ ABCD is a rhombus. Its diagonals intersect in the point P. So we get four congruent right angled triangles. Sides of each right angled triangle are \(\frac{1}{2}\) l(AC) and \(\frac{1}{2}\) l(BD). Areas of all these four triangles are equal.

Area of rhombus ABCD = 4 × A(Δ APB)

= 4 × \(\frac{1}{2}\) × l(AP) × l(BP)

= 2 × \(\frac{l(AC}{2}×\frac{l(BD}{2}\)

= \(\frac{1}{2}\) × l(AC) × l(BD)

 Area of a trapezium :

A trapezium's area is calculated by considering the distance between its parallel sides.

Formula: Area = \(\frac{1}{2}\) × sum of the lengths of parallel sides × height

Derivation: The area of a trapezium can be subdivided into two right-angled triangles and one rectangle. Summing these parts leads to the general formula.

Area of trapezium ABCD = \(\frac{1}{2}\) × h [l(DC) + l(AB)]

Area of a Triangle :

Advanced Triangle Measurement: Heron’s Formula

When the height of a triangle is unknown, but the lengths of all three sides (a, b, c) are provided, Heron’s Formula is employed.

Calculate the Semiperimeter (s): s = \(\frac{a+b+c}{2}\)

Apply the Formula: Area = \(\sqrt{s(s-a)(s-b)(s-c)}\)

Area of figures having irregular shape :

In practical scenarios, such as measuring fields or plots, figures often have irregular shapes. Two primary methods are used for these calculations:

(i) Division into Known Polygons

Irregular polygons are divided into smaller, manageable shapes such as triangles and trapeziums. The total area is the sum of the areas of these sub-figures.

Sub-figure Type Required Data for Calculation
Right-angled Triangle Base and perpendicular height
Trapezium Lengths of parallel sides and height
General Triangle Three side lengths (using Heron's Formula)

Area of polygon ABCDE = A(Δ AQB) + A(□ AQRE) + A(Δ ERD) + A(Δ BCD)

 (ii) Graph Paper Approximation

For closed figures with highly irregular boundaries, area can be estimated using graph paper:

Complete Squares: Counted as 1 sq cm each.

  • Partial Squares (> \(\frac{1}{2}\) area): Counted as 1 sq cm.
  • Half Squares (\(\frac{1}{2}\) area): Counted as 0.5 sq cm.
  • Small Partial Squares (< \(\frac{1}{2}\) area): These are ignored (0 sq cm).
  • Accuracy: The smaller the squares on the graph paper, the more accurate the approximation.

Area of a circle :

Suppose we have a circle of radius 'r' and diameter 'd' then

Area of the circle = πr2

Circumference of the circle = 2πr or πd

Land Measurement Units :

The revenue department utilizes a decimal system for recording land areas. The following table illustrates the conversions between various units:

Unit Metric Equivalent Additional Notes
1 Are 100 sq m Approximately 1 Guntha
1 Hectare 100 Are (10,000 sq m) Standardized decimal unit
1 Guntha ≈ 100 sq m Practical/traditional unit
1 Acre ≈ 0.4 Hectare Practical/traditional unit

 

PDF of this Chapter
Rs 8

-Kitabcd Academy Offer-

To Buy Notes(Rs.5)+ Solution(Rs.5) PDF of this chapter
Price : Rs.10 / Rs.8

Click on below button to buy PDF in offer (20% discount)

Useful Links

Main Page : – Maharashtra Board Class 8th Mathematics   – All chapters notes, solutions, videos, test, pdf.

Previous Chapter : Chapter 14-Compound interest – Online Notes

Next Chapter : Chapter 16- Surface area and Volume – Online Notes

Leave a Reply

Your email address will not be published. Required fields are marked *