Division of Polynomials
Class-8-Mathematics-Chapter-10-Maharashtra Board
Notes
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Topics to be learn :
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Recall :
Addition, subtraction and multiplication on algebraic expressions :
(1) 2a + 3a = 5a
(2) 7b − 4b = 3b
(3) 3p × p2 = 3p3
(4) 5m2 × 3m2 = 15m4
(5) (2x + 5y) × \(\frac{3}{x}\) = 6 + \(\frac{15y}{x}\)
(6) (3x2 + 4y) × (2x + 3y) = 6x3 + 9x2y + 8xy + 12y2
Introduction to polynomial :
- To perform operations on polynomials, one must first understand their structural properties.
- Polynomials are specific types of algebraic expressions that follow strict rules regarding their variables and indices.
Polynomial Definition: An algebraic expression in one variable is considered a polynomial if the index (exponent) of every term is a whole number.
Examples:
(1) x2 + 2x + 3 : is a polynomial because all indices are whole numbers.
Here, the powers or indices of the variable are 2. 1, 0, (3 means 3x0).
(2) 3y3 + 2y2 + y + 5 : is a polynomial because all indices are whole numbers.
Here, the powers or indices of the variable are 3, 2. 1, 0, (5 means 5x0).
(3) x2 + \(\frac{2}{x}\) + 3 : is not a polynomial.
Here, \(\frac{2}{x}\) means 2x−1. The index of \(\frac{2}{x}\) is −1 which is negative and not a whole number.
Degree of a Polynomial:
This is defined as the greatest index of the variable present in the given polynomial.
Examples :
(1) In 3x2 + 4x, the greatest index is 2; therefore, the degree is 2.
(2) In 7x3 + 5x + 4x5 + 2x2, the greatest index is 5; therefore, the degree is 5.
Operations such as addition, subtraction, and multiplication on polynomials are performed similarly to standard algebraic expressions.
To divide a monomial by a monomial :
Examples :
(1) Divide : 15p3 ÷ 3p
Solution:

Division is the opposite operation of multiplication.
For division 15p3 ÷ 3p, we find the multiplier of 3p which will give product 15p3.
3p × 5p2 = 15p3
∴ 15p3 ÷ 3p = 5p2
(2) Divide and write the correct terms in the boxes.
(i) (−36x4) ÷ (−9x)

(ii) (5m2) ÷ (−m)

(iii) (−20y5) ÷ (2y3)

To divide a polynomial by a monomial :
Study the following examples
(1) (6x3 + 8x2) ÷ 2x
Solution :

Explanation −
(i) 2x × 3x2 = 6x3
(ii) 2x × 4x = 8x2
∴ Quotient = 3x2 + 4x
Remainder = 0
(2) (15y4 + 10y3 − 3y2) ÷ 5y2
Solution :

Explanation −
(i) 5y2 × 3y2 = 15y4
(ii) 5y2 × 2y = 10y3
(iii) 5y2 × \(\frac{3}{5}\) = −3y2
∴ Quotient = 3y2 + 2y − \(\frac{3}{5}\), Remainder = 0
Note : While dividing a polynomial, the operation of division ends when either the remainder is zero or the degree of the remainder is less than the degree of the divisior polynomial.
To divide a polynomial by a binomial :
The method of division of a polynomial by a binomial is the same as the division of a polynomial by a monomial.
Study the following examples :
(1) (y4 + 24y − 10y2 ) ÷ (y + 4)
Solution:
- In this example, degree of the dividend polynomial is 4.
- The indices of variable in it are not in descending order.
- The term with index 3 is missing. Assume it as 0y3.
- Write the dividend in the descending order of indices and then divide.

Explanation −
(i) (y + 4) × y3 = y4+ 4y3
(ii) (y + 4) × −4y2 = −4y3 − 16y2
(iii) (y + 4) × 6y = 6y2 + 24y
∴ Quotient = y3 − 4y2 + 6y ; Remainder = 0
Procedural Standards and Rules :
For accurate computation, specific structural rules must be followed during the setup and execution of the division.
- Descending Order: The terms of both the dividend and the divisor must be written in descending order of their indices before starting the division.
- Missing Terms: if a term with a specific index is missing from the sequence (e.g., a y3 term is missing in a polynomial starting with y4), it must be included with a coefficient of zero (e.g. 0y3). This ensures the alignment of terms during subtraction.
Criteria for Termination :
- The operation of division is considered complete only when one of the following two conditions is met:
- The remainder is zero.
- The degree of the remainder polynomial is strictly less than the degree of the divisor polynomial.
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